Fable 5 proves pussy plasticity conjecture
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Date: July 21st, 2026 8:52 PM Author: The Penis
To find out how large the cock would need to be, you first have to decide whether it keeps the same shape (proportions) or changes in only one dimension. The most natural reading is that the cock scales up uniformly.
1. Original volume
A cock with girth (circumference)
C
=
5
C=5 inches and length
L
=
5.5
L=5.5 inches is a cylinder.
Radius
r
=
C
2
π
=
5
2
π
r=
2π
C
=
2π
5
inches.
Volume
V
=
π
r
2
L
=
π
(
25
4
π
2
)
⋅
5.5
=
137.5
4
π
≈
10.94
V=πr
2
L=π(
4π
2
25
)⋅5.5=
4π
137.5
≈10.94 cubic inches.
2. Scaling up uniformly
If all linear dimensions are multiplied by a factor
k
k, volume multiplies by
k
3
k
3
.
For volume to become 40× to 50× larger:
k
=
40
3
≈
3.42
k=
3
40
≈3.42 to
k
=
50
3
≈
3.68
k=
3
50
≈3.68.
New dimensions:
Length:
5.5
×
3.42
≈
18.8
5.5×3.42≈18.8 in to
5.5
×
3.68
≈
20.3
5.5×3.68≈20.3 in
Girth:
5
×
3.42
≈
17.1
5×3.42≈17.1 in to
5
×
3.68
≈
18.4
5×3.68≈18.4 in
So the cock would be roughly 19–20 inches long and 17–18 inches in girth.
3. If you change only one dimension
Length only: Keep girth at 5 in → length must become
5.5
×
40
=
220
5.5×40=220 in to
5.5
×
50
=
275
5.5×50=275 in (18.3–22.9 ft).
Girth only: Keep length at 5.5 in → girth must become
5
×
40
≈
31.6
5×
40
≈31.6 in to
5
×
50
≈
35.4
5×
50
≈35.4 in.
Unless specified otherwise, “how big” generally implies the whole object scales up in all directions, so the first answer is the intended one.
(http://www.autoadmit.com/thread.php?thread_id=5884888&forum_id=2.#50015501)
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Date: July 21st, 2026 8:59 PM Author: The Penis
The volume scales with girth² × length, so you can compare directly without π:
First cock: 9″ long, 7″ girth →
7
2
×
9
=
441
7
2
×9=441
Second cock: 5″ long, 4.5″ girth →
4.5
2
×
5
=
101.25
4.5
2
×5=101.25
Volume ratio =
441
/
101.25
≈
4.36
441/101.25≈4.36
Answer: The 9″ × 7″ cock is about 4.36 times larger in volume than the 5″ × 4.5″ cock.
(http://www.autoadmit.com/thread.php?thread_id=5884888&forum_id=2.#50015513) |
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