ITT some basic quant interview questions
| Peach location | 02/04/13 | | hyperactive center incel | 02/04/13 | | Clear station | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | hyperactive center incel | 02/04/13 | | lilac selfie orchestra pit | 02/04/13 | | Peach location | 02/04/13 | | hyperactive center incel | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | Primrose Ladyboy Mad Cow Disease | 02/04/13 | | Milky cheese-eating mediation queen of the night | 02/04/13 | | Opaque thriller crackhouse | 02/04/13 | | Primrose Ladyboy Mad Cow Disease | 02/05/13 | | bright boyish stock car macaca | 02/08/13 | | Peach location | 02/04/13 | | hyperactive center incel | 02/04/13 | | umber affirmative action associate | 02/04/13 | | contagious pistol | 02/04/13 | | crawly dull yarmulke locus | 02/04/13 | | charismatic twisted circlehead public bath | 02/04/13 | | insanely creepy disrespectful messiness sanctuary | 02/04/13 | | charismatic twisted circlehead public bath | 02/04/13 | | Milky cheese-eating mediation queen of the night | 02/04/13 | | charismatic twisted circlehead public bath | 02/04/13 | | razzle smoky potus | 02/04/13 | | Peach location | 02/04/13 | | hyperactive center incel | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | hyperactive center incel | 02/04/13 | | crawly dull yarmulke locus | 02/04/13 | | lilac selfie orchestra pit | 02/04/13 | | dun immigrant | 02/04/13 | | umber affirmative action associate | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | Useless buck-toothed site pisswyrm | 02/04/13 | | talented zippy native | 02/04/13 | | Useless buck-toothed site pisswyrm | 02/04/13 | | Garnet tanning salon | 02/05/13 | | at-the-ready indigo church building community account | 02/04/13 | | contagious pistol | 02/04/13 | | Black hell dysfunction | 02/05/13 | | contagious pistol | 02/04/13 | | Useless buck-toothed site pisswyrm | 02/04/13 | | contagious pistol | 02/04/13 | | Cerise flirting base gunner | 02/04/13 | | Sinister honey-headed telephone | 02/05/13 | | Sinister honey-headed telephone | 02/05/13 | | flatulent curious nowag ape | 02/05/13 | | Thirsty Wonderful Hospital | 02/08/13 | | Nubile fragrant masturbator | 02/05/13 | | dun immigrant | 02/04/13 | | hyperactive center incel | 02/04/13 | | dun immigrant | 02/04/13 | | contagious pistol | 02/04/13 | | dun immigrant | 02/04/13 | | contagious pistol | 02/04/13 | | dun immigrant | 02/04/13 | | contagious pistol | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | Milky cheese-eating mediation queen of the night | 02/04/13 | | Peach location | 02/04/13 | | Pea-brained mustard whorehouse fat ankles | 02/04/13 | | dun immigrant | 02/04/13 | | contagious pistol | 02/04/13 | | 180 disgusting rigor | 02/04/13 | | Internet-worthy Stubborn Casino | 02/08/13 | | Well-lubricated orchid market jap | 02/04/13 | | Peach location | 02/04/13 | | contagious pistol | 02/04/13 | | Peach location | 02/04/13 | | dun immigrant | 02/04/13 | | talking blood rage | 02/04/13 | | Milky cheese-eating mediation queen of the night | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | contagious pistol | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | Peach location | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | talking blood rage | 02/04/13 | | crawly dull yarmulke locus | 02/04/13 | | dun immigrant | 02/04/13 | | Peach location | 02/04/13 | | Burgundy motley private investor | 02/04/13 | | sepia slimy stag film coffee pot | 02/04/13 | | sepia slimy stag film coffee pot | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | Pea-brained mustard whorehouse fat ankles | 02/04/13 | | Peach location | 02/04/13 | | talented zippy native | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | talented zippy native | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | talented zippy native | 02/04/13 | | contagious pistol | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | contagious pistol | 02/04/13 | | talented zippy native | 02/04/13 | | contagious pistol | 02/04/13 | | contagious pistol | 02/04/13 | | Excitant Lavender Dragon Preventive Strike | 02/04/13 | | flatulent curious nowag ape | 02/05/13 | | Vivacious therapy meetinghouse | 02/05/13 | | Peach location | 02/04/13 | | contagious pistol | 02/04/13 | | Provocative principal's office gaping | 02/04/13 | | contagious pistol | 02/04/13 | | Milky cheese-eating mediation queen of the night | 02/04/13 | | contagious pistol | 02/04/13 | | elite field | 02/05/13 | | Peach location | 02/05/13 | | Provocative principal's office gaping | 02/04/13 | | Rose step-uncle's house | 02/04/13 | | talking blood rage | 02/04/13 | | Peach location | 02/04/13 | | contagious pistol | 02/04/13 | | dun immigrant | 02/04/13 | | contagious pistol | 02/04/13 | | Navy gas station | 02/04/13 | | contagious pistol | 02/04/13 | | Navy gas station | 02/04/13 | | dun immigrant | 02/04/13 | | contagious pistol | 02/04/13 | | Navy gas station | 02/04/13 | | Navy gas station | 02/04/13 | | contagious pistol | 02/04/13 | | Navy gas station | 02/04/13 | | flatulent curious nowag ape | 02/04/13 | | Rose step-uncle's house | 02/04/13 | | talking blood rage | 02/04/13 | | contagious pistol | 02/04/13 | | aqua brunch | 02/05/13 | | Peach location | 02/04/13 | | contagious pistol | 02/04/13 | | Rose step-uncle's house | 02/04/13 | | Peach location | 02/04/13 | | contagious pistol | 02/04/13 | | dun immigrant | 02/04/13 | | dun immigrant | 02/04/13 | | Peach location | 02/05/13 | | Vermilion Floppy Property Wrinkle | 02/05/13 | | Peach location | 02/04/13 | | Rose step-uncle's house | 02/04/13 | | Navy gas station | 02/04/13 | | talking blood rage | 02/04/13 | | Chocolate dog poop | 02/04/13 | | contagious pistol | 02/04/13 | | Chocolate dog poop | 02/04/13 | | poppy multi-colored house | 02/05/13 | | Chocolate dog poop | 02/05/13 | | poppy multi-colored house | 02/05/13 | | Provocative principal's office gaping | 02/04/13 | | Black hell dysfunction | 02/05/13 | | aqua brunch | 02/05/13 | | Sinister honey-headed telephone | 02/05/13 | | aqua brunch | 02/08/13 | | shaky electric furnace trailer park | 02/05/13 | | aqua brunch | 02/05/13 | | flatulent curious nowag ape | 02/05/13 | | aqua brunch | 02/05/13 | | Ruddy pit multi-billionaire | 02/05/13 | | Sinister honey-headed telephone | 02/05/13 | | Mint abode quadroon | 02/05/13 | | fiercely-loyal comical boistinker library | 02/05/13 | | aqua brunch | 02/05/13 | | bright boyish stock car macaca | 02/08/13 | | Peach location | 07/25/17 |
Poast new message in this thread
Date: February 4th, 2013 4:57 PM Author: Peach location
sample questions for intro level business analyst type job (not quant but you have to have an intuitive grasp of numbers)
starting with the easiest:
there's a pond with lily pads on it. every day, the number of lily pads doubles. on the 40th day, the pond is completely covered. on which day is the pond half covered?
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568146) |
Date: February 4th, 2013 5:00 PM Author: Peach location
#3
what is the sum of all numbers from 1-99? no calculator/outside aids allowed. also describe how you would do the calculation
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568179) |
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Date: February 4th, 2013 5:03 PM Author: lilac selfie orchestra pit
1 + 99 = 100.
2 + 98 = 100.
and so on. so we end up with 49 pairs with a value of 100 each. 49 x 100 = 4900. We have 1 50 left over. 4950.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568200) |
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Date: February 4th, 2013 5:26 PM Author: Useless buck-toothed site pisswyrm
594
I sample the sum of the first eleven numbers in the series: 1+2+3+4+5+6+7+8+9+10+11 = 66.
From this sample, I can reasonably estimate that each sample of eleven numbers in the overall series sums up to 66, and the total number of samples of eleven numbers is 99/11 = 9. therefore the total sum for 9 samples would be 66*9 = 594 +/- 7.4 at 95% confidence
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568365) |
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Date: February 5th, 2013 7:48 PM Author: Nubile fragrant masturbator
Imagine a 99 x 99 stack of unit area blocks. Then divide the stack in half by a diagonal line going top left to bottom right.
The question is equivalent to asking what is the total area of the blocks either entirely to the left of the line or cut by the line.
(99 x 99)/2 gives you the area to the left of the line but then you have to account for an extra 99 half-blocks for those blocks cut by the line, so:
(99 x 99)/2 + (99 x 0.5) = 4950
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22576162) |
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Date: February 4th, 2013 5:19 PM Author: dun immigrant
no, this one has at least one solution
edit:
oh, i see why this is confusing everyone. ABC is a 3 digit number, not A*B*C
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568310) |
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Date: February 4th, 2013 5:19 PM Author: Pea-brained mustard whorehouse fat ankles
ABC=813
CBA=318
BBCB=1131
pretty simple once you realize that B has to be 1. if you are adding 2 3-digit numbers, the largest possible sum is 1998 (999+999). so B must be 1. C+A must equal 1, so the possible combinations are like 7, 4 or 8, 3, etc. i plugged in 8, 3 first and got the right answer.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568311) |
Date: February 4th, 2013 5:15 PM Author: Peach location
#4
how would you obtain the sum of all results of a set of 1-10 multiplication tables?
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568286) |
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Date: February 4th, 2013 5:17 PM Author: dun immigrant
sum of the first row is 5*11 (using the gauss formula above)
each row is n*(first row) where n is the value of the row digit
so 55 + 2*55 + ... + 10*55
iow, (1+2+...+10)*55 = 55^2
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568303) |
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Date: February 4th, 2013 5:50 PM Author: Milky cheese-eating mediation queen of the night
sum(sum(ij),i=1..10),j=1..10)
sum(j*sum(i,i=1..10),j=1..10)
sum(j*55,j=1..10)
55*sum(j,j=1..10)
55*55
3025
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568531) |
Date: February 4th, 2013 5:28 PM Author: Peach location
You are offered to play a game of chance. A fair coin is tossed repeatedly until you get the first tails, at which point the game ends and you get the prize. The prize "pot" starts at $1 and doubles each time you get heads. So for instance, if you get heads the first toss, the pot becomes $2. If you get heads again the second toss, the pot becomes $4. If you get heads the third time, the pot becomes $8. If the fourth toss gives you the tail of the coin, you win and take home the $8 prize.
Before you play, you must pay a fee to enter this game. The question is, what's the maximum amount you're willing to pay in order to play this game?
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568387) |
Date: February 4th, 2013 5:30 PM Author: talented zippy native
Got this one during my b-school interview:
You have a lamp that you need to set on a timer. You want it to come on for two periods daily: 5-8am and 5-8pm. You have an unlimited number of light timers that each can allow power to the lamp for one period (think: those cheap Ikea timers that would allow the light to be on for one period per day). You can run these timers in sequence.
How many of these timers would the lamp require, and each set to what period, so that it will be on for these two time periods during the day?
edit: 24 hour timers. Lamp has one cord going to a single outlet. Multiple timers would run in sequence.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568397)
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Date: February 4th, 2013 6:23 PM Author: Excitant Lavender Dragon Preventive Strike
you god damn retards
2 timers
5am to 8pm
5pm to 8am
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568725) |
Date: February 4th, 2013 5:35 PM Author: Peach location
this is a well known one
One hundred ants are dropped on a meter stick. Each ant is traveling either to the left or the right with constant speed 1 meter per minute. When two ants meet, they bounce off each other and reverse direction. When an ant reaches an end of the stick, it falls off.
At some point all the ants will have fallen off. The time at which this happens will depend on the initial configuration of the ants.
Question: over ALL possible initial configurations, what is the longest amount of time that you would need to wait to guarantee that the stick has no more ants?
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568436) |
Date: February 4th, 2013 5:46 PM Author: Peach location
A shopkeeper says she has two new baby beagles to show you, but she doesn't know whether they're male, female, or a pair.
You tell her that you want only a male, and she telephones the fellow who's giving them a bath.
"Is at least one a male?" she asks him. "Yes!" she informs you with a smile.
What is the probability that both beagles are male?
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568507) |
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Date: February 4th, 2013 5:53 PM Author: dun immigrant
cases where one is a male:
MF, FM, MM
in 1/3, both are male
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568542) |
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Date: February 4th, 2013 5:58 PM Author: contagious pistol
This is the way it was explained to me, but I find this suspect. You are treating it as though there are "positions" for the dogs. But as I see it, there is only one dog and the other dog, so there should really only be two cases
MF
MM
where the second spot represents "the other dog."
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568560)
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Date: February 4th, 2013 6:34 PM Author: Navy gas station
No you have 4 scenarios:
Mgroom Mbride
Mgroom Fbride
Fgroom Fbride
Fgroom Mbride (lol)
You've eliminated the FF wedding, but you have a 1/3 shot at dat MM
edit: If you know in advance that it is 1 man marrying either a man or a woman, then you are right. But if you are going in blind and ask someone "is atleast 1 partner a man", then the odds play out as I showed above.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568794) |
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Date: February 4th, 2013 6:00 PM Author: Navy gas station
You have Puppy A and Puppy B. Four equally likely outcomes:
Aboy Bgirl
Aboy Bboy
Agirl Bgirl
Agirl Bboy
The phone call eliminates one outcome (Agirl, Bgirl)
Of the remaining possible outcomes, 1/3 is Boy-Boy
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568567) |
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Date: February 4th, 2013 6:27 PM Author: Navy gas station
With the wording of the problem, you assume that the person on the phone knows the sex of both puppies.
It's similar to the monty hall problem, where the fact that the host knows that he is showing you a losing door changes the odds vs if he were to show you a door at random and it happens to be a loser.
If he had only looked at one dog, and it happened to be a male, your numbers are correct.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568762) |
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Date: February 4th, 2013 7:10 PM Author: contagious pistol
Here's another way to think about it:
The guy on the phone is effectively saying "I have two puppies here, one to my right and one to my left, and at least one of them (the one I'm looking at) is male"
There are four possibilities now:
1) The one he is looking at, R, is male, and L is also male
2) The one he is looking at, L, is male, and R is also male
3) The one he is looking at, R, is male, and L is female
4) The one he is looking at, L, is male, and R is female
The odds of two males becomes 50%. I don't see why this is any more or less a reasonable way to interpret the problem than the standard answer.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568990) |
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Date: February 4th, 2013 6:40 PM Author: dun immigrant
ok, i think i've got it.
my original idea was to paddle in a circle with a radius of r/2 (a circle inscribed so that r of the pond is its diameter). this had the virtue of forcing the monster to run towards a spot that you were moving away from. sadly, he only has to cover 3/2 pi r in the time you take to travel 1/2 pi r, so you still lose b/c of his speed advantage. (he only needs to be 3x as fast as you to arrive at the same moment).
this made me realize that the monster's speed advantage always allows him to catch you on an arced course whenever the distance you travel is that of a circle with arc >= 1/4r
so i think you win by 1) paddling in a circle with arc < r/4, which should allow you to get to a point where he is trailing the point your bow is pointing at, and then 2) go straight to the shore
do i get to be a janitor for quants with this answer
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568833) |
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Date: February 4th, 2013 6:09 PM Author: Navy gas station
1 black pearl in one bag
99 black pearls and 100 white pearls in the other
edit: I mean, assuming you have to place every pearl in a bag. Otherwise, just dump those TTT white pearls.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568623) |
Date: February 5th, 2013 6:58 PM Author: Black hell dysfunction
most of these are all pseudo-intellectual gay ass questions.
only the ones that required inventing a formula are worth looking at.
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22575719) |
Date: February 5th, 2013 7:33 PM Author: Mint abode quadroon
I got this one:
"Think out loud and let us listen to how you estimate the cans of paint it will take to paint the Verrazano Narrows Bridge."
(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22576048) |
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